JavaScript Array lastIndexOf() Method

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# JavaScript Array lastIndexOf() Method

JavaScript Array Object

## Example

Search an array for the item "Apple":

var fruits = ["Banana", "Orange", "Apple", "Mango"];
var a = fruits.lastIndexOf("Apple");

The result of a will be:

2

Meaning that "Apple" is located at position 2 in the array.

Try it yourself »

## Definition and Usage

The lastIndexOf() method searches the array for the specified item, and returns it's position.

The search will start at the specified position, or at the end if no start position is specified, and end the search at the beginning of the array.

Returns -1 if the item is not found.

If the item to search for is present more than once, the lastIndexOf method returns the position of the last occurence.

Tip: If you want to search from start to end, use the indexOf() method

## Browser Support

The lastIndexOf() method is not supported in Internet Explorer 8 and earlier.

## Syntax

array.lastIndexOf(item,start)

## Parameter Values

Parameter | Description
--- | ---
item | Required. The item to search for
start | Optional. Where to start the search. Negative values will start at the given position counting from the end, and search to the beginning

## Return Value

Type | Description
--- | ---
Number | The position of the specified item, otherwise -1

## Technical Details

JavaScript Version: | 1.6

## More Examples

## Example

Search an array for the item "Apple":

var fruits=["Banana","Orange","Apple","Mango","Banana","Orange","Apple"];
var a = fruits.lastIndexOf("Apple");

The result of a will be:

6
Try it yourself »

## Example

Search an array for the item "Apple", starting the search at position 4:

var fruits=["Banana","Orange","Apple","Mango","Banana","Orange","Apple"];
var a = fruits.lastIndexOf("Apple",4);

The result of a will be:

2
Try it yourself »

JavaScript Array Object

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